NYT Pips Hints & Answers Today: April 15, 2026

NYT Pips Answers & Guide – April 15 2026

Edited by Ian Livengood • Solved by WordFinder Tips
NYT Pips Solution April 15, 2026

Table of Contents

Today’s Puzzle Overview

NYT Pips drops a fresh grid every day. April 15 2026 brings three difficulty tiers, each with its own set of dominoes and region constraints. The goal is to place every domino so every region satisfies its rule – equals, less, greater, sum, empty, or unequal.

Easy Tier – Quick Wins

The easy board is a 2 × 7 rectangle. Six dominoes are available, ranging from double‑ones to a 0‑5 tile. Five regions demand exact matches, while two single‑cell zones enforce “less than 2” and “greater than 4”. The layout forces a single logical chain: the 0‑0 domino must sit in the low‑value cell, and the 5‑0 piece fills the high‑value spot.

Medium Tier – Balanced Challenge

Medium expands to a 4 × 7 grid. Eight dominoes include high‑value pairs like 5‑2 and low‑value 0‑1. Nine regions mix empty, sum, less, greater, equals, and an unequal block. The puzzle’s heart lies in the central column where a sum‑3 region meets a less‑1 cell – only a 1‑2 domino can satisfy both.

Hard Tier – Full‑Blown Logic

Hard pushes the board to 7 × 7 with fourteen dominoes. Fifteen regions span equals, sums, empties, and a tricky unequal cluster covering four cells. The biggest obstacle is a sum‑23 region that consumes most high‑value pips. You must balance the 6‑6 domino against lower tiles to hit the exact total.

Interactive Pips Solution

Tap the domino tiles in the hand below to reveal their position on the board.

<2
>4

<1
3
3
2
>5

4
23
<5
4
7

🧠 Deep Mechanic Analysis & Optimal Paths

Understanding how each rule interacts with the domino set is the key to speed. Below we break down the logical flow for each difficulty.

Logic Flow for Easy

Start with the “greater than 4” cell at (1,6). Only the 5‑0 domino can satisfy that, so lock it in place. Next, the “less than 2” cell at (1,0) forces the 0‑0 tile. The remaining four dominoes must fill the three equals regions. Because the region covering (0,4),(0,5),(1,5) needs three identical values, the only way is to place the double‑3 domino across (0,4)–(0,5) and the 2‑3 domino across (0,2)–(0,1). The final placement of the 1‑1 domino completes the last equals region.

Strategy for Medium

Identify forced placements first. The empty region at (0,2)-(1,2) eliminates any domino that would occupy those cells – the 0‑1 tile must go elsewhere. The “less than 1” cell at (0,3) can only hold a 0‑0 or 0‑1 domino; the 0‑1 domino is already needed for the sum‑3 region at (2,0), so place a 0‑0 there. Next, the two sum‑3 cells at (2,0) and (2,5) each need a 1‑2 combination; the 1‑2 domino fits both, but only one copy exists, so pair a 2‑1 domino with a 1‑2 in the adjacent region. The unequal block covering (3,2)-(4,3) forces all four numbers to differ – use the 5‑2, 4‑0, 5‑1, and 3‑2 dominoes in a rotating pattern. Finally, the greater‑than‑5 cell at (3,4) demands the 5‑2 domino, sealing the solution.

Hard Tier – Advanced Reasoning

The equals block in the top‑left corner (0,0‑2,1) locks the 1‑4 and 4‑5 dominoes together. The sum‑4 region at (0,2)-(0,3) can only be satisfied by a 1‑3 or 2‑2 pair; the 2‑2 domino is unavailable, so place the 1‑3 domino there. The massive sum‑23 region spanning the fourth column (0,4‑3,4) must absorb the highest pips: 6‑6, 5‑5, 4‑5, and 5‑2. Arrange them so the column totals 23, leaving a 2‑3 domino for the adjacent less‑5 cell at (2,3). The empty cells at (3,0) and (4,0) are perfect spots for the 0‑0 and 0‑1 dominoes, keeping the sum‑4 region at (5,0‑6,0) balanced. The final unequal block (5,3‑6,4) requires all four numbers to differ; distribute 5‑5, 4‑4, 3‑5, and 2‑6 across it. This cascade resolves every region without conflict.

✅ Today’s Winning Solutions

Difficulty First 5 Domino Placements (row,col)
Easy
  • [(1,0),(1,1)]
  • [(2,3),(3,3)]
  • [(0,3),(1,3)]
  • [(0,4),(0,5)]
  • [(0,2),(0,1)]
Medium
  • [(1,5),(2,5)]
  • [(1,4),(1,3)]
  • [(4,2),(4,3)]
  • [(1,1),(1,2)]
  • [(1,0),(2,0)]
Hard
  • [(0,2),(0,1)]
  • [(2,1),(3,1)]
  • [(5,4),(6,4)]
  • [(1,4),(2,4)]
  • [(6,3),(6,2)]

Post-Game Analysis

Every placement above respects the region constraints. In Easy, the forced 5‑0 domino at (1,6) drives the rest of the chain. Medium’s unequal block forces a rotation that eliminates duplicate values. Hard’s sum‑23 column is the linchpin; swapping any high‑value domino breaks the total. Review the full solution if you need to verify each region’s final count.

Frequently Asked Questions

  • What is today’s Pips puzzle? It is a 7 × 7 grid with fourteen dominoes, each bearing two pip values, and fifteen region rules you must satisfy.
  • How do the symbols in Pips work? Symbols indicate the rule type: equals means all cells share the same value, sum requires the total to match the target, less/greater set an upper or lower bound, empty forces a zero, and unequal demands all numbers differ.
  • Do touching domino tiles have to match? No. Only the region constraints matter; adjacent dominoes can have any values as long as each region’s rule is met.